khan509 khan509
  • 21-05-2018
  • Mathematics
contestada

How do you write the vertex form equation of the parabola #y=2x^2 +11x-6#?

Respuesta :

altavistard
altavistard altavistard
  • 23-05-2018
The easist way to find the vertex is to complete the square:

y=2x^2 +11x-6  =>  y=2[ x^2 + (11/2)x  + (11/2)^2   - (11/2)^2 ]  - 6  

This can be rewritten as 
                                y = 2[(x+11/2)^2 ] -(121/4) - 24/4

                                y = 2 (x+11/2)^2 - 145/4

this is the equation in vertex form.  The vertex is at (-11/2, -145/4).
Answer Link

Otras preguntas

n/5 - 5n/10= 1/5 please explain. I semi understand it but still explain thoroughly.
how do i find the displacement of an object using a velocity vs. time graph? i also have to draw position and acceleration graphs and im not sure how to get the
17+2x=31-5x What would the answer be i tried answering it but.i forgot how to solve it
Find all solutions of given equation 2cosx-1=0
When is the quotient greater than 1
A triangle has height 4 ft and area 32 ft2. What is the lenght of the base?
What are some fun facts about the number 25?
What is the difference between Weight and Mass?Please give a fair amount of detail!
Which area is NOT considered part of the British Isles? North Wales South Wales Portugal England
What times what equal to 17 and 25