Sample size = n = 2500
Sample Proportion = p = 0.86
Confidence Level = 99%
Z-value for the confidence level = z = 2.576 (This Value comes from the z-table)
The formula for Margin of Error is:
[tex]E=z* \sqrt{ \frac{p(1-p)}{n} } [/tex]
Using the given values, we get:
[tex]E=2.576* \sqrt{ \frac{0.86(0.14)}{2500} } \\ \\
E=0.0179 [/tex]
Thus, the margin of error would be 0.0179 or 1.79%
