Respuesta :

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[tex]k:y=m_1x+b\\l:y=m_2x+c\\\\k\ ||\ l\ if\ m_1=m_2\\\\k\ \perp\ l\ if\ m_1m_2=-1[/tex]

We have:
[tex]m_1=\dfrac{3}{-5}=-\dfrac{3}{5};\ m_2=\dfrac{-5}{-3}=\dfrac{5}{3}\\\\m_1m_2=-\dfrac{3}{5}\cdot\dfrac{5}{3}=-1[/tex]
Answer: a perpendicular slope.