For this case we have the following inequality: [tex] \frac{x-9}{7x+2} \leq 0[/tex] Solving for the numerator we have: [tex]x-9 \leq 0[/tex] [tex]x \leq 9[/tex] Solving for the denominator we have: [tex]7x+2\ \textgreater \ 0[/tex] [tex]7x\ \textgreater \ -2[/tex] [tex]x \ \textgreater \ \frac{-2}{7} [/tex] Therefore, the solution is given by: [tex] \frac{-2}{7} \ \textless \ x \leq 9 [/tex] The graph that shows this solution is the graphic number 3. Answer: option 3
we know that the denominator cannot be zero, therefore the value of x = -2 /7 cannot belong to the domain of the function 7x+2=0-----> x=-2/7-----> x=-0.29
using a graph tool see the attached figure
the solution is the interval (-2/7, 9]---------> (-0.29, 9] the value of -0.29 is not included in the solution
