bowenlucas1452 bowenlucas1452
  • 21-07-2018
  • Mathematics
contestada

Find the length and width of a rectangle whose perimeter is 40 feet and whose area is 96 square feet.

Respuesta :

ralphwx1 ralphwx1
  • 21-07-2018
Let the length and width be l and w, respectively. Then, perimeter = 2(l + w) = 40, and area = lw = 96. In other words:
l + w = 20
lw = 96
From here, we could guess and check to get that the length and width are 12 and 8, but let’s do this rigorously:
By the first equation, l = 20 - w
Substituting into the second equation:
(20 - w) * w = 96
w^2 - 20w + 96 = 0
w^2 - 20w + 100 = 4
(w - 10)^2 = 4
w - 10 = 2 or -2
w = 12 or 8
The rest is trivial.
Answer Link

Otras preguntas

why did thousands of settlers head west during the 1800s
what are the positive aspects of stereotypes, if any?
Which of the following are not a spore-bearing vascular plant? a. ferns b. cycads c. club mosses d. horsetails
what forces led to the rise of the mongols?
i need help writing an equation from a graph
a bank allows university students a 1000 overdraft facility on their bank accounts. in one month a student was 675 overdrawn. the next month the same student
The radius of a circle is 4. The diameter is 8. The radius of a triangle is 8. The diameter is 16. Which shape has the least amount of square feet?
find the midpoint of the line segment joining the points P1 and P2P1=(3,-4); P2=(5,4)
What is the ranges for f(x) = 2x + 4 when the domains are 1, 2, 3, and 10
I have been stuck on this question and i would like to know how to solve it ? A mother horse and a baby horse walk 10 miles from point A to point B. The mother’