Respuesta :

gmany

[tex]f(x)=ax^2+bx+c\\\\a\ vertex\ (h,\ k)\\\\h=\dfrac{-b}{2a},\ k=f(h)\\\\We\ have:\\\\h(x)=-x^2+8x+15\\\\a=-1,\ b=8,\ c=15\\\\h=\dfrac{-8}{2(-1)}=\dfrac{-8}{-2}=4\\\\k=h(4)=-4^2+8(4)+15=-16+32+15=31\\\\Answer:\ (4,\ 31)[/tex]

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