josegabi57 josegabi57

21-10-2018
Mathematics

contestada

solve for Y

[tex] \sqrt{y + 8 } = y + 6[/tex]

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konrad509 konrad509

21-10-2018

[tex]y+8\geq0 \wedge y+6\geq0\\y\geq-8 \wedge y\geq -6\\y\geq-6\\\\\sqrt{y+8}=y+6\\y+8=(y+6)^2\\y+8=y^2+12y+36\\y^2+11y+24=0\\y^2+3y+8y+24=0\\y(y+3)+8(y+3)=0\\(y+8)(y+3)=0\\y=-8 \vee y=-3\\\\-8\not\geq-6\\\\\boxed{x=-3}[/tex]

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