melisasvr
melisasvr melisasvr
  • 23-10-2018
  • Mathematics
contestada

How do you find the quadratic function with vertex (-2,5) and point (0,9)?

Respuesta :

tramserran
tramserran tramserran
  • 23-10-2018

Answer: y = (x +2)² + 5

Step-by-step explanation:

y = a(x - h)² + k where "a" is the leading coefficient and (h, k) is the vertex

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a":  (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

-5            -5

4  =  a(4)

÷4   ÷4  

 1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


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