tonytlan06
tonytlan06 tonytlan06
  • 25-11-2018
  • Mathematics
contestada

Solve for x:
logₓ 125 = 3/2

Respuesta :

jimrgrant1 jimrgrant1
  • 25-11-2018

x = 25

using the law of logarithms

• [tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex], hence

125 =[tex]x^{3/2}[/tex]

x = [tex]\sqrt[3]{125^2}[/tex] = [tex]\sqrt[3]{15625}[/tex] = 25



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