A bob of mass of 0.18 kilograms is released from a height of 45 meters above the ground level. What is the balue of the kinetic energy gained by the bob at the ground level?

Respuesta :

K.E = mgh at bottom

K.E = 0.18*10*45

K.E = 81J

K.E at the bottom will be equal to P.E at hight.