Answer:
33
Step-by-step explanation:
1st integer =x
2nd integer = x+1
3rd integer = x+2
4th integer = x+3
sum of four consecutive integers is 130
x+(x+1)+(x+2)+(x+3) = 130
Combine like terms
4x+6 = 130
Subtract 6 from each side
4x+6-6 = 130-6
4x = 124
Divide by 4
4x/4 = 124/4
x=31
Find the third number
x+2 =31+2 = 33
