kayleerodgers kayleerodgers

25-02-2019
Mathematics

contestada

factor completely:
12x^5 + 6x^3 + 8x^2

a- prime
b- 2(6x^5+3x^3+4x^2)
c- 2x(6x^4+6x^2+4x)
d- 2x^2(6x^3+3x+4)

Respuesta :

jimrgrant1 jimrgrant1

25-02-2019

Answer:

d

Step-by-step explanation:

Given

12[tex]x^{5}[/tex] + 6x³ + 8x² ← factor out 2x² from each term

= 2x²(6x³ + 3x + 4) → d

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