ligittiger12806
ligittiger12806 ligittiger12806
  • 26-03-2019
  • Mathematics
contestada

There are 12 contestants in a coloring contest. Three ribbons will be awarded. How many different ways could the ribbons be awarded?

Respuesta :

DizzyBerco
DizzyBerco DizzyBerco
  • 06-04-2019

Answer:

1320 ways

Step-by-step explanation:

Here we have a situation where 3 ribbons will be awarded to 3 of the 12 contestants. We can use the permutation formula, because the order of awarding the ribbons matters.

The permutation formula is:

[tex]_{n}P_{k}=\dfrac{n!}{(n-k)!}[/tex]

n = 12

k = 3

Now that we have our variables, let's plug them into the formula.

[tex]_{12}P_{3}=\dfrac{12!}{(12-3)!}[/tex]

[tex]_{12}P_{3}=\dfrac{12!}{9!}[/tex]

[tex]_{12}P_{3}=1320[/tex]

So there are 1320 different ways that the contestants will be awarded.

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