Answer:
[tex]\large\boxed{Q6.\ \sin X\approx0.778}\\\boxed{Q7.\ x\approx5.9}[/tex]
Step-by-step explanation:
Q6.
[tex]\sin\theta=\dfrac{opposite}{hypotenuse}[/tex]
We have
[tex]opposite=14\\\\hypotenuse=18[/tex]
Substitute:
[tex]\sin X=\dfrac{14}{18}=\dfrac{14:2}{18:2}=\dfrac{7}{9}=0.777...\approx0.778[/tex]
Q7.
Use sine.
We have
[tex]opposite=x\\\\hypotenuse=8\\\\\alpha=48^o\\\\\sin48^o\approx0.7431[/tex]
Substitute:
[tex]\dfrac{x}{8}=0.7431[/tex] multiply both sides by 8
[tex]x=5.9448\to x\approx5.9[/tex]
