For this case we must evaluate the following expression:
[tex]\sqrt [3] {64}[/tex]
By definition, we know that:
[tex]64 = 2 * 2 * 2 * 2 * 2 * 2 = 2 ^ 6[/tex]
Also, by definition of properties of powers and roots we have;
[tex]\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}[/tex]
So, rewriting the expression we have:
[tex]\sqrt [3] {2 ^ 6} = 2 ^ {\frac {6} {3}} = 2 ^ 2 = 4[/tex]
Answer:
Option A
