Answer:
[tex]\large\boxed{\sqrt{228}-\sqrt{50}=2\sqrt{57}-5\sqrt2}[/tex]
Step-by-step explanation:
[tex]\sqrt{228}-\sqrt{50}=\sqrt{4\cdot57}-\sqrt{25\cdot2}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{57}-\sqrt{25}\cdot\sqrt2\\\\=2\sqrt{57}-5\sqrt2[/tex]
