saavvyxbuu7189 saavvyxbuu7189
  • 21-08-2019
  • Physics
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A particle with a mass of 6.67x10^-27 kg has a de Broglie wavelength of 7.22 pm. What is the particle's speed?

Respuesta :

Karabo99
Karabo99 Karabo99
  • 24-08-2019

Answer:

The speed of the particle is 13767.35 m/s.

Explanation:

given the mass m = 6.67×10^-27 kg of particle and moving with a speed v. the momentum of the particle is given by P = m×v and the planck constant  h = 6.63×10^-34 m^2×kg/s. the wavelength is λ = 7.22 pm ≈7.22×10^-12 m

The de Broglie wavelength is given by:

λ = h/P

λ = h/(m×v)

v = h/λ×m

  = (6.63×10^-34)/[(7.22×10^-12)×(6.67×10^-27)]

  = 13767.35 m/s

Therefore, the speed of the particle is 13767.35 m/s.

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