Answer:
The width of the slit is [tex]3.51\times10^{-7}\ m[/tex].
Explanation:
Given that,
Wavelength = 470 nm
Angle = 51.0°
We need to calculate the width of slit
Using formula of width
[tex]2d\sin\theta=n\lambda[/tex]
[tex]d=\dfrac{n\lambda}{2\sin\theta}[/tex]
Where, n = number of fringe
[tex]\lambda[/tex] = wavelength
Put the value into the formula
[tex]d=\dfrac{1\times470\times10^{-9}}{2\sin51}[/tex]
[tex]d=3.51\times10^{-7}\ m[/tex]
Hence, The width of the slit is [tex]3.51\times10^{-7}\ m[/tex].
