Respuesta :

[tex]A=(0,1); B=( \frac{1}{2}, 0) \\ y=ax+b \left \{ {{1=0a+b} \atop {0= \frac{1}{2}+b }} \right. \\ \left \{ {{1=b} \atop { \frac{1}{2}a=-b}} \right. \\ \left \{ {{b=1} \atop {a=-2}} \right. y=-2x+1[/tex]