brezzy2
brezzy2
25-05-2016
Mathematics
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the zeros of the function f(x)=3x^2-3x-6 are
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konrad509
konrad509
25-05-2016
[tex]3x^2-3x-6=0\\ 3(x^2-x-2)=0\\ x^2-x-2=0 x^2+x-2x-2=0\\ x(x+1)-2(x+1)=0\\ (x-2)(x+1)=0\\ x=2 \vee x=-1 [/tex]
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