Mixedemotions9583 Mixedemotions9583
  • 21-10-2019
  • Mathematics
contestada

Solve the following exponential equations.
(2x)^x = 8^x

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 21-10-2019

Answer:

  x = 4

Step-by-step explanation:

Dividing by 8^x, we have ...

  (2x/8)^x = 1

  (x/4)^x = 1

  x(log(x) -log(4)) = 0 . . . . . taking logarithms

The values of x that make the factors of this product 0 are ...

  x = 0 . . . . . extraneous, as 0^0 is indeterminate

  log(x) = log(4)    ⇒    x = 4

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