Answer:
A'(0) = 657.06
Explanation:
[tex]A_{(t)} =699(t+1)^{0.94}[/tex]
To know the fall in prices on 2002 we need to calculate A't
to derivate a power, the current value the power multiplies and we subtract one from it:
As the base is a funtion we need to derivate that as well:
dt(t+1) = 1
[tex]A_{(t)} =699(0.94)\times (t+1)^{0.94 - 1} \times dt(t+1)[/tex]
[tex]A_{(t)} =657.06\times (t+1)^{-0.06} \times 1[/tex]
[tex]\frac{657.06}{(t+1)^{0.06}}[/tex]
Know we calculate for t = 0
[tex]\frac{657.06}{(0+1)^{0.06}}[/tex]
A'(0) = 657.06
