calculate the final centigrade temperature required to change 20 litres of gas at 120 degree Celsius and 1 atmosphere to 25 litres at 2 atmosphere​

Respuesta :

Explanation:

pv=nRT

1×20=(273+120)×0.0082×N

2×25=(273+T)×0.082×N

(273+T)=1965/2

T=609.5