Respuesta :

kinousukephan

Answer:

Step-by-step explanation:

[tex]9x^2[/tex] + 64 = 0

<=> x = ( -b ± [tex]\sqrt{b^{2} - 4ac }[/tex]) / 2a

<=> x = [tex]( 0^2 ± \sqrt{0^{2} - 4.9.64 }[/tex]) / 2.9

<=> x = ±(8/3)i

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