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24-11-2019
Mathematics

contestada

prove that determinant of a(b+c) bc 1 b(c+a) ca 1 c(a+b) ab 1 =0

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myself9583 myself9583

07-10-2021

Answer:

This is a cheap way my teacher told me but if you divide by 0 you can get it but for a actual problem you cannot divide by 0

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