Answer:
d≅1.3
Step-by-step explanation:
Given a line of equation
[tex]ax + by + c = 0[/tex]
And the point [tex](x_0,y_0)[/tex]
The distance from the line to the point is given by
[tex]\displaystyle d=\frac {|ax_{0}+by_{0}+c|}{\sqrt {a^{2}+b^{2}}}[/tex]
In the question we have
[tex]-x+y+6=0[/tex] and P(-9,-3)
Replacing the values in the formula:
[tex]d=\frac {|(-1)(-9)+(1)(-3)+6|}{\sqrt {(-9)^{2}+(-3)^{2}}}[/tex]
[tex]d=\frac {|9-3+6|}{\sqrt {81+9}}[/tex]
[tex]d=\frac {12}{\sqrt {90}}=\frac {4}{\sqrt {10}}[/tex]
d≅1.3
