Answer:
x + 1 + 4√(x-3)
Step-by-step explanation:
Given: [tex]$ (\sqrt{x - 3} + 2)^2 $[/tex]
We know that: (a + b)² = a² + b² + 2ab
Using this formula, we expand the given expression:
⇒ [tex]$ (\sqrt{x - 3} + 2)^2 = (\sqrt{x - 3})^2 + 2.\sqrt{x - 3}. 2 + 2^2 $[/tex]
⇒ [tex]$ x - 3 +4\sqrt{x - 3} + 4 $[/tex]
⇒ [tex]$ (\sqrt{x - 3} + 2)^2 $[/tex] = x + 1 +4√(x - 3).
