25-11-2019
Chemistry

contestada

calculate moles of 3.9g of sodium

Respuesta :

25-11-2019

Answer:

[tex]\boxed{\text{0.17 mol}}[/tex]

Explanation:

[tex]\text{M$_{r}$ of Na} = 22.99\\\text{Moles} = \text{3.9 g } \times \dfrac{\text{1 mol}}{\text{22.99 g}} = \text{0.17 mol}\\\\\text{ The sample contains $\boxed{\textbf{0.17 mol}}$ of Na}[/tex]

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