francine2210 francine2210
  • 23-01-2020
  • Chemistry
contestada

How many milliliters of 10.0 M HCl ( aq ) are needed to prepare 790.0 mL of 1.00 M HCl ( aq )

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dsdrajlin
dsdrajlin dsdrajlin
  • 24-01-2020

Answer:

79.0 mL

Explanation:

Given data

  • Initial concentration (C₁): 10.0 M
  • Initial volume (V₁): ?
  • Final concentration (C₂): 1.00 M
  • Final volume (V₂): 790.0 mL

In order to find the volume required of the concentrated solution, we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 1.00 M × 790.0 mL/10.0 M

V₁ = 79.0 mL

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