Answer:
0.70 moles will be produced
Explanation:
step 1: start with mol HCl, go to mol CaCl2 then do the same for mol Ca(OH)2
step 2: determine limited reagent
step 3: check answer
EQUATION: 2 HCl + Ca(OH)2 → CaCl2 + 2 H2O
Calculation:
(1.4 mol HCl) x (1 mol CaCl2 / 2 mol HCl)
= 0.70 mol CaCl2
