Solution:
Given that,
Points are W(2, 5), U(4, 3)
Distance between two points is given as:
[tex]d = \sqrt{(y_2-y_1)^2 + (x_2-x_1)^2}[/tex]
From given,
[tex](x_1, y_1) = (2, 5)\\\\(x_2, y_2) = (4, 3)[/tex]
Substituting the values we get,
[tex]d = \sqrt{(3-5)^2+(4-2)^2}\\\\d = \sqrt{(-2)^2 + (2)^2}\\\\ d = \sqrt{4+4}\\\\d = \sqrt{8}\\\\d = 2.8284[/tex]
[tex]d \approx 2.8[/tex]
Thus the distance between the pair of points is 2.8 units
