kellerpaula kellerpaula
  • 23-03-2020
  • Mathematics
contestada

Trigonometry
Trigonometric Equations
0 ≤ x ≤ 2 π , solve the equation, sin 2θ =-1

Respuesta :

surjithayer10 surjithayer10
  • 23-03-2020

Answer:

Step-by-step explanation:

[tex]sin ~2~ \theta=-1=-sin~ \pi /2\\=sin ~(\pi +\pi /2),sin ~(2\pi +\pi +\pi /2)\\=sin~(3\pi /2),sin~(7\pi /2)\\2 ~\theta=3 \pi/2,7 \pi /2\\\theta=3\pi /4,7\pi /4[/tex]

Answer Link
amna04352
amna04352 amna04352
  • 23-03-2020

Answer:

θ = 3π/4, 7π/4

Step-by-step explanation:

sin 2θ = -1

basic angle = π/2

2θ = 2π - π/2 = 3π/2,

3π/2 + 2π = 7π/2

θ = 3π/4, 7π/4

Answer Link

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