Respuesta :

wegnerkolmp2741o

Answer:

b<-12 or b>-12

(-∞,-12]U[-12,∞)

Step-by-step explanation:

0.5b > -6 or 3b + 16 <-8 + b

I solve these separately

0.5b > -6

Divide by .5 on each side

0.5b/.5 > -6/.5

b >-12  

or

3b + 16 <-8 + b  

subtract b from each side

3b-b + 16 <-8 + b -b

2b+16<-8

Subtract 16 from each side

2b+16-16<-8-16

2b< -24

Divide each side by 2

2b/2 <-24/2

b<-12

b<-12 or b>-12

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