brodie85 brodie85

24-03-2020
Mathematics

contestada

tan A(secA-cosA)/sinA

Respuesta :

kenlingdad kenlingdad

24-03-2020

Answer:

tan A(secA-cosA)/sinA = tan²A

Step-by-step explanation:

tanA (secA - cosA) / sinA = (SinA / CosA) (secA - cosA) / sinA

= (1 / CosA) (1 / CosA - CosA) = 1 / Cos²A - 1 = (1 - Cos²A) / Cos²A

= sin²A / Cos²A

= tan²A

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