Given:
In the given triangle ΔABC,
AB = 9 unit
AC = 2 unit
To find the value of ∠ABC.
Formula
From trigonometric ratio we get,
[tex]sin \theta = \frac{opposite}{hypotenuse}[/tex]
Let us take, ∠ABC = [tex]\theta[/tex]
With respect [tex]\theta[/tex], AC is the opposite side and AB is the hypotenuse.
So,
[tex]sin \theta = \frac{AC}{AB}[/tex]
or, [tex]sin \theta[/tex] = [tex]\frac{2}{9}[/tex]
or, [tex]\theta = sin^{-1} (\frac{2}{9} )[/tex]
or, [tex]\theta= 12.84^\circ[/tex]
Hence,
The value of ∠ABC is 12.84°.
