Answer:
16
Step-by-step explanation:
The existence of the constant rate of change is given the ratio of y to x is the same. Then:
[tex]k_{1} = \frac{80}{5}[/tex]
[tex]k_{1} = 16[/tex]
[tex]k_{2} = \frac{64}{4}[/tex]
[tex]k_{2} = 16[/tex]
[tex]k_{3} = \frac{96}{6}[/tex]
[tex]k_{3} = 16[/tex]
In consequence, the constant rate of change is 16.
