Answer:
83000 m/s
Explanation:
Using
F = Bqv....................... Equation 1
Where F = Force experienced by the charge, B = magnetic field q = charge of the particle, v = speed of the particle.
make v the subject of the equation
v = F/Bq.................... Equation 2
Given: q = 5.2×10⁻¹⁹ Coulombs, F = 9.5×10⁻¹⁵ Newtons, B = 2.2×10⁻¹ Tesla
Substitute into equation 2
v = 9.5×10⁻¹⁵ /(5.2×10⁻¹⁹×2.2×10⁻¹)
v = 8.3×10⁴ m/s
v = 83000 m/s
