Answer:
3[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Given the complex number z = a + bi then the absolute value is
| z | = [tex]\sqrt{a^2+b^2}[/tex]
Given - 4 - [tex]\sqrt{2}[/tex] i, then absolute value is
[tex]\sqrt{(-4)^2+(-\sqrt{2})^2 }[/tex]
= [tex]\sqrt{16+2}[/tex]
= [tex]\sqrt{18}[/tex] = [tex]\sqrt{9(2)}[/tex] = 3[tex]\sqrt{2}[/tex]
