micaylacook135 micaylacook135
  • 21-05-2020
  • Mathematics
contestada

find the equation of a line parallel to 2x-3y=9 that passes through the point (1, -3)

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redr9364 redr9364
  • 21-05-2020

Answer:

y = 2/3x - 11/3

Step-by-step explanation:

2x-3y=9

Rearrange to find the parallel gradient:

-3y = -2x+9

y = 2/3x -3

M(gradient) = 2/3

M(parallel gradient) = 2/3

Substitute the gradient and the points point A and B into the equation :

y-b = m(x-a)

y - (-3) = 2/3(x-1)

3y + 9 = 2x -2

3y = 2x -11

y = 2/3x - 11/3

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