Answer:
A
Step-by-step explanation:
Firstly we find the x value. x-7=0; x=7
Secondly we introduce x value in 1st ecuation. So
(7-3)^2 +(y+1)^2=16, 16+y^2+2y+1=16,
Consider this ecuation: y^2+2y+1=0
y1=( -b+Δ)/ 2a, y2= (-b-√Δ)/2a, Δ=√b^2-4ac=√4-4=0
y1,2= -2/2= -1
1 Real solution x=7 and y= -1.
