Answer:
V = 53.83 L
Explanation:
Given data:
Number of moles = 2.00 mol
Temperature = 45°C (45+273 = 318 K)
Pressure = 98.6 KPa (98.6/101 = 0.97 atm)
Volume of gas = ?
Solution:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
0.97 atm × V = 2.00 mol × 0.0821 atm.L/mol. K × 318 K
V = 52.22 atm.L/0.97 atm
V = 53.83 L
