Answer:
Option A
Step-by-step explanation:
We know that for an eqn. [tex]ax^{2} +bx+c=0[/tex] , the quadratic formula is =
[tex]x = \frac{-b+\sqrt{b^{2}-4ac } }{2a} or \frac{-b-\sqrt{b^{2}-4ac } }{2a}[/tex]
So using quadratic eqn. for [tex]x^{2} -6x-5=0[/tex]
[tex]x =\frac{-(-6)+\sqrt{(-6)^{2}-4*1*(-5) } }{2*1}or\frac{-(-6)-\sqrt{(-6)^{2}-4*1*(-5) } }{2*1}[/tex]
[tex]=> x = \frac{6+\sqrt{36+20} }{2} or\frac{6-\sqrt{36+20} }{2}[/tex]
[tex]=>x = \frac{6+\sqrt{56} }{2} or\frac{6-\sqrt{56} }{2}[/tex]
