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  • 23-10-2016
  • Mathematics
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How do you solve 3log_3 4a=3?

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Аноним Аноним
  • 23-10-2016
3 log₃ 4a=3

1)a(log_b c)=log_b c^a
log₃(4a)³=3

2) log_a x=n  ⇔  a^n=x
log₃ (4a)³=3 ⇔  3³=(4a)³
27=64a³
a³=27/64
a=∛(27/64)
a=3/4

Answer: a=3/4
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