Respuesta :

apologiabiology
solve for x in each


5x+7>-8
minus 7
5x>-15
divide both sides by 5
x>-3


3x+7≤19
minus 7 both sides
3x≤12
divide 3
x≤4
we have
x>-3 and x≤4
compound is any value that satisfys both

x>-3 and x≤4
-3<x≤4
-3 to 4, not including -3, but including 4