Answer:
The product is;
(80x^2-560x+ 980)/9
Step-by-step explanation:
Here, we want to get the product of the two smaller numbers
let the mid number be y
3/4 = 2x-7/y
3y = 8x-28
y = (8x-28)/3
Let the biggest be z
3/5 = 2x-7/z
3z = 10x -35
z = (10x-35)/3
The product of the two other numbers is thus;
(10x-35)/3 * (8x-28)/3
= (10x-35)(8x-28)/9
(80x^2-280x - 280x + 980)9
= (80x^2 - 560x + 980)/9
