kayleebarnum5263 kayleebarnum5263
  • 25-01-2021
  • Mathematics
contestada

What are the vertical asymptotes of the function f(x) = 4x+8/x^2+3x-4

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 29-01-2021

Answer:

1 and -4

Step-by-step explanation:

The vertical asymptote of a function is gotten by equating the denominator of such function to zero.

Given

f(x) = 4x+8/x^2+3x-4

The vertical asymptotes is expressed as;

x^2+3x-4 = 0

Factorize

x^2+4x-x-4 = 0

x(x+4) -1 (x+4) = 0

(x-1)(x+4) = 0

x-1 = 0 and x+4 = 0

x = 1 and x = -4

Hence the vertical asymptotes of the function are 1 and -4

Answer Link

Otras preguntas

HELP ME ASAP AND I WILL GIVE 5.0 RATING AND BRAINLIEST.
Third parties play a significant role in the election process because they advocate what ?
please help me please
Mettez les mots dans le bon order. (Including capital letter and punctuation). REFER TO THE PICTURE
seiko deposits $3500 into an account that pts 5.8% annual interest monthly. what’s the balance after 8 years
Angle FGH is a right angle. The measure of angle JGH is 50. The measure of angle FGJ is What is the value of x?
A project whose positive exceed its is more likely to be enacted that one that is the opposite
Determine the rational zeros for the function f(x)=8x^(3)-6x^(2)-23x+6. a. -(1)/(2),(1)/(4),2 c. -1(1)/(2),(1)/(4),2 b. 1(1)/(2),(1)/(4),-2 d. -1(1)/(2),-(1)/(4
I need a essay about “how words shape our lives”maximum 150-160 word please help me ASAP
What is the area if this figure?