Step-by-step explanation:
Given,
Base of the triangle
[tex]2 \sqrt{6} [/tex]
Hypotenuse of the triangle = 5
Height of the triangle = x
Therefore, According to Pythagoras Theorem,
[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]
[tex] = > {(2 \sqrt{6)} }^{2} + {x}^{2} = {5}^{2} [/tex]
[tex] = > 24 + {x}^{2} = 25[/tex]
[tex] = > {x}^{2} = 25 - 24[/tex]
[tex] = > {x}^{2} = 1[/tex]
[tex] = > x = \sqrt{1} [/tex]
[tex] = > x = 1[/tex]
Hence, the required value of x is 1.
