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23-02-2021
Chemistry

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What is the amount of aluminum chloride produced from 40 moles of chlorine and excess aluminum?

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Аноним Аноним

23-02-2021

Answer: Molar mass of Al = 26.98 g/mol

mass of Al = 12 g

mol of Al = (mass)/(molar mass)

= 12/26.98

= 0.4448 mol

According to balanced equation

mol of AlCl3 formed = moles of Al

= 0.4448 mol

Answer: 0.445 mol

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