Respuesta :

ProdigyL1901

Answer:

Simplify 32(x^2+4x)

32x^2+128x=16(x^2+4x+3)

simplify 16(x^2+4x+3)

32x^2+128x=16x^2+64x+48

subtract 16x^2 from both sides

subtract 64x from both sides

subtract 16x^2 and 32x^2

subtract 64x from 128x

x=−2+√7,−2−√7 answer

hope this helps :))