katoriajohnson17 katoriajohnson17
  • 22-03-2021
  • Mathematics
contestada

In AJKL, solve for x.

In AJKL solve for x class=

Respuesta :

jimrgrant1 jimrgrant1
  • 22-03-2021

Answer:

x ≈ 66.73

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan27° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{KL}{JK}[/tex] = [tex]\frac{34}{x}[/tex] ( multiply both sides by x )

x × tan27° = 34 ( divide both sides by tan27° )

x = [tex]\frac{34}{tan27}[/tex] ≈ 66.73 ( to 2 dec. places )

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